How to calculate liqueur alcohol percentage and final volume
I'm planning to make an homemade liqueur, like Limoncello, but with oranges. To begin, I've added orange zests to 500 grams of 96% alcohol. Now, I'm puzzled about the sugar syrup.
In the beginning I thought that 500 grams of alcohol + 500 grams of water + 500 grams of sugar = 1.5 liter of liqueur at 33% of alcohol. After some research I learned it's not that simple. I should consider density, convert mass to volume, and probably something else.
So here I am, looking for a tool/spreadsheet/formula to do this math. Something as simple as: given the amount (in grams) of alcohol, sugar and water, you will obtain a solution of a certain amount in liter with a certain percentage of alcohol.
Any help would be appreciated, I'm a total newbie.
Topic alcohol alcohol-content homebrew
Category Mac