How can I show <li> only if custom field has content

Question

How can I show <li> only if custom field has content

Ricardo Villela

2014年11月7日 17:48

I have the following code:

font size="2"Pistas:/font/p
ul
li
  ?php

echo types_render_field("pista-1a", array("argument1"="value1","argument2"="value2","argument2"="value2"));

?li
?php

echo types_render_field("pista-1b", array("argument1"="value1","argument2"="value2","argument2"="value2"));

? /li/ul       '

As you can see... I manually inserted

in every item, but sometimes not all fields have contents, so in this case, the

bullets show with no content in front of them.. how can I change the code to insert

only if the custom field is not empty.... (I'm using Types Plugin)

Sorry for my basic coding, I'm not a programmer and I'm learning a little as I try to adapt my theme to my needs

Thanks a lot folks!

Topic plugin-types php customization Wordpress

Category Web

Howdy_McGee · Accepted Answer · 2014年11月7日 17:48

Again, I'm not familiar with Advanced Custom Fields but you may be able to store the returned value into a variable then test if that variable is empty, like so:

<?php
    $pista1a = types_render_field("pista-1a", array("argument1"=>"value1","argument2"=>"value2","argument2"=>"value2"));
?>
<ul>

  <?php if( ! empty( $pista1a ) ) : ?>

    <li>
        <?php echo $pista1a; ?>
    </li>

  <?php endif; ?>

</ul>

How can I show <li> only if custom field has content

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